GATE Mechanical Engineering (ME) 2018 Shift 2 Solved Paper

Question : 25 of 65

Marks: +1, -0

A=[\table 1 , 2 , 3 ; 0 , 4 , 5 ; 0 , 0 , 1]

then

\det(A^{-1})

is (correct to two decimal places).

Solution:

A=[\table 1 , 2 , 3 ; 0 , 4 , 5 ; 0 , 0 , 1]

|A|=4

|A^{-1}|=\;{1}/{|A|}=\;{1}/{4}

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