GATE Mechanical Engineering (ME) 2018 Shift 1 Solved Paper

Question : 13 of 65

Marks: +1, -0

A bar of uniform cross section and weighing

100 {N}

is held horizontally using two massless and inextensible strings

S_{1}

and

S_{2}

as shows in the figure.

Tension in the springs are

Solution:

T_{1}+T_{2} \;\; =100 {N}

....(i)

Σ M_{A} \;\; =0

T_{2} ⋅ \;{L}/{2} \;\; =100 × \;{L}/{2}

∴T_{2} \;\; =100 {N}

T_{1} \;\; =0 {N}

Comments: This can also be inferred from fact that if T1 is finite then the bar will notremain horizontal.

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