GATE Mechanical Engineering (ME) 2018 Shift 1 Solved Paper

Let ‘a’ be the side of square, then length and breadth of rectangle are ‘a+10 and ‘a+5’ respectively
Given that,
Area of rectangle= Area of Square $+650$
$\left(\mathit{a}+10\right)\left(\mathit{a}+5\right)={\mathit{a}}^2+650$
${\mathit{a}}^2+15\mathit{a}+50={\mathit{a}}^2+650$
$15\mathit{a}=600$
$\mathit{a}=40$
Area of rectangle $={\mathit{a}}^2+650$
Area of rectangle $=1600+650=2250$