A curve passes through the point (x = 1, y = 0) and satisfies the differential equation \frac{dy}{dx} = {x^{2} + y^{2}}/{2y} + \frac{y}{x}. The equation that describes the curve is

Correct Answer is : ln(1+y2x2)=x−1

\ln (1 + {y^{2}}/{x^{2}}) = x−1

\frac{1}{2}\ln (1 + {y^{2}}/{x^{2}}) = x−1

\frac{1}{2}\ln (1 + \frac{y}{x}) = x−1

GATE Electronics and Communications (EC) 2018 Solved Paper

Question : 44 of 65

Marks: +1, -0

A curve passes through the point (x = 1, y = 0) and satisfies the differential equation

\;{dy}/{dx} = \;{x^{2}\;+\;y^{2}}/{2y} + \;{y}/{x}.

The equation that describes the curve is

Go to Question:

Prev Question

Next Question