The general solution of the differential equation \frac{dy}{dx} = \frac{1 + cos2y}{1−\cos ⁡2x} is

Correct Answer is : tany+cotx=c(cisaconstant)

\tan\:y\:−\:\cot\:x\: = \:c (c\:is\:a\:constant)

\tan\:x\:−\:\cot\:y\: = \:c (c\:is\:a\:constant)

\tan\:y\: + \:\cot\:x\: = \:c (c\:is\:a\:constant)

\tan\:x\: + \:\cot\:Y\: = \:c (c\:is\:a\:constant)

GATE Electronics and Communications (EC) 2015 Shift 2 Solved Paper

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The general solution of the differential equation

\;{dy}/{dx} = \;{1\;+\;cos2y}/{1−\cos\;⁡2x}

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