A plane wave propagating in air with E^{\to} = (8a^{\^}_{x} + 6a^{\^}_{y} + 5a^{\^}_{z}) e^{j (\omega t + 3x−4y) }\frac{V}{m} is incident on a perfectly conducting slab positioned at x ≤ 0. The E^{\to} field of the reflected wave is

Correct Answer is : (−8a^x−6a^y−5a^z)ej(ωt−3x−4y)Vm

(−8a^{\^}_{x}−6a^{\^}_{y}−5a^{\^}_{z}) e^{j (\omega t + 3x + 4y) }\frac{V}{m}

(−8a^{\^}_{x} + 6a^{\^}_{y}−5a^{\^}_{z}) e^{j (\omega t + 3x + 4y) }\frac{V}{m}

(−8a^{\^}_{x}−6a^{\^}_{y}−5a^{\^}_{z}) e^{j (\omega t−3x−4y) }\frac{V}{m}

(−8a^{\^}_{x} + 6a^{\^}_{y}−5a^{\^}_{z}) e^{j (\omega t−3x−4y) }\frac{V}{m}

GATE Electronics and Communications (EC) 2012 Solved Paper

Question : 14 of 65

Marks: +1, -0

A plane wave propagating in air with

E↖{→} = (8a↖{\^}_{x} + 6a↖{\^}_{y} + 5a↖{\^}_{z}) e^{j (ω t + 3x−4y) }\;{V}/{m}

is incident on a perfectly conducting slab positioned at x ≤ 0. The

E↖{→}

field of the reflected wave is

Go to Question:

Prev Question

Next Question