GATE Electrical Engineering (EE) 2021 Solved Papers

Question : 59 of 65

Marks: +1, -0

The waveform shown in solid line is obtained by clipping a full-wave rectified sinusoid (shown dashed). The ratio of the RMS value of the full-wave rectified waveform to the RMS value of the clipped waveform is ______________. (Round off to 2 decimal places.)

Your Answer:

Validate

Solution:

{V}_{ {\rms} \;\text " Clipped "\;}=[\;{1}/{π} ∫↙{0}^{\;{π}/{4}} {V}_{ {m}}^{2} \sin ^{2} θ ⋅ {d} θ+∫↙{\;{π}/{4}}^{\;{3 π}/{4}}(\;{ {V}_{ {m}}}/{√{2}})^{2} ⋅ {d} θ+∫↙{\;{3 π}/{4}}^{π} {V}_{ {m}}^{2} \sin ^{2} θ ⋅ {d} θ]^{\;{1}/{2}}

{V}_{ {\text "rms clipped"}}=0.58 {V}_{ {m}}

{V}_{ {\text "rms Unclipped"}}= {V}_{ {rms}}

for

{FWR}=\;{ {V}_{ {m}}}/{√{2}}

\;{V_{\;\text "rms Unclipped "\;}}/{V_{\;\text "rms Clipped "\;}}=\;{\;{V_{ {m}}}/{√{2}}}/{0.58 V_{ {m}}}=1.219

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