GATE Electrical Engineering (EE) 2021 Solved Papers

Question : 57 of 65

Marks: +1, -0

Consider the buck-boost converter shown. Switch

{Q}

is operating at

25 {kHz}

and

0.75

duty-cycle. Assume diode and switch to be ideal. Under steady-state condition, the average current flowing through the inductor____________A.

Solution:

I_{L}=\;{α V_{d c}}/{R(1-α)^{2}}=\;{0.75 × 20}/{10(1-0.75)^{2}}=24 {A}

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