A solution of the ordinary differential equation {d^{2}y}/{dt^{2}} + 5\frac{dy}{dt} + 6y = 0 is such that y (0) = 2 and y (1) = −\frac{1−3e}{e^{3}}. The value of \frac{dy}{dt} (0) is ______.

GATE Electrical Engineering (EE) 2015 Shift 1 Solved Paper

Question : 37 of 65

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A solution of the ordinary differential equation

\;{d^{2}y}/{dt^{2}} + 5\;{dy}/{dt} + 6y = 0

is such that

y (0) = 2

and

y (1) = −\;{1−3e}/{e^{3}}

. The value of

\;{dy}/{dt} (0)

is ______.

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