For the circuit shown in the figure, the voltage and current expressions are v(t) = E 1 sin(ωt) + E 3 sin(3ωt) and i(t) = I 1 sin(ωt - Φ 1 ) + I 3 sin(3ωt - Φ 3 ) + I 5 sin(5ωt) The average power measured by the Wattmeter is

Correct Answer is : 12[E1I1cosφ1+E3I3cosφ3]

\frac{1}{2}E_{1}I_{1}\cos\phi _{1}

\frac{1}{2}[E_{1}I_{1}\cos\phi _{1} + E_{1}I_{3}\cos\phi _{3} + E_{1}I_{5}]

\frac{1}{2}[E_{1}I_{1}\cos\phi _{1} + E_{3}I_{3}\cos\phi _{3}]

\frac{1}{2}[E_{1}I_{1}\cos\phi _{1} + E_{3}I_{1}\cos\phi _{1}]

GATE Electrical Engineering (EE) 2012 Solved Paper

Question : 35 of 65

Marks: +1, -0

For the circuit shown in the figure, the voltage and current expressions are
v(t) = E₁sin(ωt) + E₃sin(3ωt) and i(t) = I₁sin(ωt - Φ₁) + I₃sin(3ωt - Φ₃) + I₅sin(5ωt)
The average power measured by the Wattmeter is

$\;{1}/{2}E_{1}I_{1}cosφ _{1}$
$\;{1}/{2}[E_{1}I_{1}cosφ _{1} + E_{1}I_{3}cosφ _{3} + E_{1}I_{5}]$
$\;{1}/{2}[E_{1}I_{1}cosφ _{1} + E_{3}I_{3}cosφ _{3}]$
$\;{1}/{2}[E_{1}I_{1}cosφ _{1} + E_{3}I_{1}cosφ _{1}]$

Validate

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