GATE Computer Science (CS) 2018 Shift 1 Solved Paper

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Question : 8 of 65

Marks: +1, -0

In the figure below,

∠ {DEC}+∠{BFC}

is equal to ────────

.

$∠{BCD}-∠{BAD}$
$∠{BAD}+∠{BCF}$
$∠{BAD}+∠{BCD}$
$∠{CBA}+∠{ADC}$

Solution:

∠ E+∠ F=?

α+q+E=180

.....(i)

α+β+F=180

......(ii)

α+β+p+q=360

....(iii)
Equation

(i) +(ii)=(iii)

α+q+ {E}+α+β+ {F}=α+β+p+q

E+F=p-α

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