GATE Civil Engineering (CE) 2020 Shift 2 Solved Paper

Sum of the odd positive integers from 1 to 100
$=1+3+5.....+99$
No. of terms $=50$
First term $=1;$ Last term $=99$
Therefore, Sum $=50\times \left(1+99\right)/2=2500$
Sum of the even positive integers from 150 to 200
No. of terms $=26$
First term $=150$; Last term $=200$
Therefore, Sum $=26\times \left(150+200\right)/2=4550$
$\therefore$ ratio $=\frac{2500}{4550}=\frac{50}{91}$