GATE Civil Engineering (CE) 2020 Shift 2 Solved Paper

Question : 62 of 65

Marks: +1, -0

The design speed of a two-lane two-way road is

60 {km} \/ {h}

and the longitudinal coefficient of friction is

0.36

. The reaction time of a driver is

2.5

seconds. Consider acceleration due to gravity as

9.8 {m} {/} {s}^{2}

. The intermediate sight distance (in

{m}

, round off to the nearest integer) required for the road is

Solution:

Given:

{V}=60 {kmph}=16.67 {m} {/} {sec}

{f}=0.36

{t}=2.5 {sec}

{g}=9.8 {m} \/ {s}^{2}

As we know,

1 {SD}=2 {SSD}

(stopping sight distance)

⇒ S S D=v t+\;{v^{2}}/{2 g f}

=16.67 × 2.5+\;{16.67^{2}}/{2 × 9.81 × 0.36}

=41.675+39.34=81.01 {m}

∴ 1 S D=2 × 81.01=162 {m}

Go to Question:

Prev Question

Next Question