GATE Civil Engineering (CE) 2020 Shift 2 Solved Paper

Question : 33 of 65

Marks: +1, -0

A fair (unbiased) coin is tossed 15 times. The probability of getting exactly 8 Heads (round off to three decimal places), is

Solution:

{x}=15

P(r=8)={ }^{n} C_{r} p^{r} q^{n-r}

={ }^{15} C_{8} p^{8} q^{15-8}

={ }^{15} {C_8} {p}^{8} {q}^{7}

P=(

probability of success in toss

)=\;{1}/{2}

q=

(probability of failure during toss)

=\;{1}/{2}

P(r=8)=15 C_8(\;{1}/{2})^{8}(\;{1}/{2})^{7}

={ }^{15} {C}_{8}(\;{1}/{2})^{15}=0.196

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