GATE Civil Engineering (CE) 2020 Shift 1 Solved Paper

Let one positive number be a other positive number = 100 – a product of number after
subtracting 5 from each number $=\left(\mathit{a}-5\right)\times \left(95-\mathit{a}\right)=0$
$\Rightarrow 95\mathit{a}-{\mathit{a}}^2-475+5\mathit{a}=0$
$\Rightarrow {\mathit{a}}^2-100\mathit{a}+475=0$
$\Rightarrow {\mathit{a}}^2-95\mathit{a}-5\mathit{a}+475=0$
$\Rightarrow \mathit{a}\left(\mathit{a}-95\right)-5\left(\mathit{a}-95\right)=0$
$\Rightarrow$ either $\mathit{a}=5$ or $\mathit{a}=95$
From, the options given 95 is the answer.