GATE Civil Engineering (CE) 2020 Shift 1 Solved Paper

Question : 23 of 65

Marks: +1, -0

The true value of

\ln (2)

0.69

. If the value of

\ln (2)

is obtained by linear interpolation between

\ln (1)

and

\ln (6)

, the percentage of absolute error (round off

Solution:

T.V

=0.69

\ln _{1}=0

\ln _{6}=1.79

from interpolating

(\ln1\ & \;\ln 6)

we get

=0.358( {mv})

\%

Error

=\;{T ⋅ v-m v}/{T . v} × 100

\%

Error

=48.11 \%

Go to Question:

Prev Question

Next Question