GATE Civil Engineering (CE) 2019 Shift 2 Solved Paper

Question : 45 of 65

Marks: +1, -0

A water treatment plant treats

6000 {m}^{3}

of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of

1.5 {m}

per hour would produce the desired removal of particles through settling in the clarifier having a depth of

3.0 {m}

. The volume of the required clarifier, (in

{m}^{3}

, round off to 1 decimal place) would be

Your Answer:

Validate

Solution:

Given data:
Flow rate

=6000 {m}^{3} {/}

day
Over flow rate

=1.5 {m} {/}

hour

=1.5 × 24 {m} {/} {day}=36 {m} {/}

day
Flow area

=\;{\;\text " Flow rate "\;}/{\;\text " over flow rate "\;}=\;{6000}/{36}

=166.67 {m}^{2}

Volume required for clarifier = Flow area

\times

depth

=166.67 × 3=500 {m}^{3}

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