GATE Civil Engineering (CE) 2019 Shift 1 Solved Paper

Question : 34 of 65

Marks: +1, -0

An element is subjected to biaxial normal tensile strains of

0.0030

and

0.0020

. The normal strain in the plane of maximum shear strain is

Solution:

Given

ε_{x}=0.0030 ; ε_{y}=0.0020

Normal stress in the plane of maximum shear strain is centre of Mohr circle.
Centre of Mohr circle

=\;{E_{x}+E_{y}}/{2}=\;{0.0030+0.0020}/{2}=\;{0.0050}/{2}=0.0025

Go to Question:

Prev Question

Next Question