GATE Civil Engineering (CE) 2019 Shift 1 Solved Paper

Question : 17 of 65

Marks: +1, -0

In a rectangular channel, the ratio of the velocity head to the flow depth for critical flow condition, is

Solution:

Velocity head for a critical flow

=\;{q^{2}}/{2 g y_{c}^{2}}=\;{y_{c}^{u}}/{2 y_{c}}=\;{1}/{2} y_{c}

So, ratio of velocity head to critical flow depth

=\;{1}/{2}

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