GATE Civil Engineering (CE) 2018 Shift 2 Solved Paper

Question : 38 of 65

Marks: +1, -0

A cable PQ of length

25 {m}

is supported at two ends at the same level as shown in the figure. The horizontal distance between the supports is

20 {m}

. A point load of

150 {kN}

is applied at point

{R}

which divides it into two equal parts.

Neglecting the self-weight of the cable, the tension (in

{kN}

, in integer value) in the cable due to applied load will be_______

Solution:

12.5^{2}=x^{2}+10^{2} ⇒ x=7.5 {m}

Bending moment at

S=0 \{

Consider the left part

\}

H_{p} × 7.5=75 × 10

H_{p}=100 {kN}

Tension in cable

=√{H_{p}^{2}+V_{ρ}^{2}}=√{75^{2}+100^{2}}=125 {kN}

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