GATE Civil Engineering (CE) 2018 Shift 1 Solved Paper

Question : 65 of 65

Marks: +1, -0

A closed tank contains

0.5 {m}

thick layer of mercury (specific gravity

=13.6

) at the bottom. A

2.0 {m}

thick layer of water lies above the mercury layer. A

3.0 {m}

thick layer of oil (specific gravity

=0.6

) lies above the water layer. The space above the oil layer contains air under pressure. The gauge pressure at the bottom of the tank is

196.2 {kN}{/}{m}^{2}

. The density of water is

1000 {kg}{/} {m}^{3}

and the acceleration due to gravity is

9.81 {m} {/} {s}^{2}

. The value of pressure in the air space is

Solution:

P_{\;\text "air "\;}

is in gauge pressure.

P_{\;\text "air "\;}+(0.6 × 10^{3})(9.81)(3)+(10^{3})(9.81)(2)+

(13.6 × 10^{3})(9.81)(0.5)=196.2 × 10^{3}

P_{\;\text "air "\;}=92.214 {kN} {/} {m}^{2}

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