What is the value of x when 81 \times (\frac{16}{25}) ^{x + 2} \div (\frac{3}{5}) ^{2x + 4} = 144\:?

GATE Civil Engineering (CE) 2017 Shift 2 Solved Paper

Question : 4 of 65

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What is the value of x when

81 × (\;{16}/{25}) ^{x + 2} ÷ (\;{3}/{5}) ^{2x + 4} = 144\:?

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