if \alpha, \beta, \gamma are the roots of equation x^{3}-4 x^{2}+x+6 then the equation roots are \frac{1}{\alpha} \frac{1}{\beta}, \frac{1}{\gamma} is

Correct Answer is : 6x3+x2−4x+1=0

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Question : 38 of 39

Marks: +1, -0

α, β, γ

are the roots of equation

x^{3}-4 x^{2}+x+6

then the equation roots are

\;{1}/{α}

\;{1}/{β}, \;{1}/{γ}

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