EPFO 2017 English Medium Solved Paper

Question : 117 of 121

Marks: +1, -0

The area of the smallest circle which contains a square area

4 cm ^{2}

inside is

Solution:

Given,

Area of ABCD(square) =

4 cm^{2}

⇒

(\Diagonal)^{2}/2=4

⇒ Diagonal =

√8cm

∴ Diameter of circle =Diagonal of square

=√8

∴

Radius of circle=

√8/2

Hence, area of circle =

πr^{2}=π(√8/2)^2

=π×8/4=2π

^2

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