EPFO 2017 English Medium Solved Paper

Let the radius of old spherical container = $\mathit{r}$
Then, the radius of new spherical container = $2\mathit{r}$
Hence, required ratio
$=$ volume of new container : Volume of old container
$\frac{4}{3}\mathit{\pi }{\left(2\mathit{r}\right)}^3:\frac{4}{3}\mathit{\pi }{\left(\mathit{r}\right)}^3$
= $8{\mathit{\pi }}^3:{\mathit{r}}^3$ $=8:1$