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Question : 62 of 160
Marks:
+1,
-0
Solution:
‌{x∈R:‌−‌<0}‌‌| 14x(x−4)−(9x−30)(x+1) |
| (x+1)(x−4) |
<0 ‌‌| 14x2−56x−(9x2−30x+9x−30) |
| (x+1)(x−4) |
<0‌‌| (14x2−56x−9x2+30x−9x+30) |
| (x+1)(x−4) |
<0‌‌| (5x2−35x+30) |
| (x+1)(x−4) |
<0‌‌<0,‌| (x−1)(x−6) |
| (x+1)(x−4) |
<0Drawn number line,
Hence,
x∈(−1,1)∪(4,6)
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