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Question : 49 of 160
Marks:
+1,
-0
Solution:
‌tan‌y‌=sin‌(x+y)+sin‌(x−y)‌tan‌y‌=2⋅sin‌(‌)⋅cos(‌)‌[∵sin‌C+sin‌D=2sin‌(‌)⋅cos(‌)]‌⇒‌‌tan‌y‌=2sin‌x⋅cos‌y‌⇒‌‌‌‌=2sin‌x‌cos‌y‌‌ On integrating ‌‌⇒‌‌∫‌dy=∫2sin‌x‌dx‌[| ‌ Let ‌t=cos‌y |
| ‌=−sin‌y |
| −dt=sin‌ydy |
]‌⇒‌‌−∫‌=2(−cos‌x)+c‌⇒‌‌−(−‌)=−2‌cos‌x+c‌⇒‌‌‌=−2‌cos‌x+c‌⇒‌‌ secy=−2‌cos‌x+c‌
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