EAMCET Engineering 2010 Solved Paper

The equation of line AB which makes an equal intercepts on positive x and y axes are‌

x

a

+‌

y

a

=1
ie, ‌‌x+y=a . . . (i)
Distance of Eq. (i) from origin =1
|‌

0+0−a

√1+1

|=1,|‌

−a

√2

|=1
‌⇒‌‌a=√2
From Eq. (i), ‌‌x+y=√2 . . . (ii)
Also given line,
2x−y=−3−√2 . . . (iii)
The intersection point of line (ii) and line (iii) is
(x0,y0)‌=(−1,√2+1)
‌ So, ‌‌‌2x0+y0‌=2(−1)+√2+1
‌=−2+√2+1=(√2−1)
‌ Hence, ‌‌‌2x0‌+y0=√2−1