EAMCET Engineering 2009 Solved Paper

Power of motor initially =P0
Let, rate of flow of motor =(x)
Since, power, P0‌=‌

‌ work ‌

‌ time ‌

=‌

mgy

t

‌=mg(‌

y

t

),
‌

y

t

=x= rate of flow of water
=mgx . . . (i)
If rate of flow of water is increased by n times, ie, (nx).
Increased power P1=‌

mgy′

t

‌=mg(‌

y′

t

)=mgn⋅x
‌=nmgx . . . (ii)
The ratio of power
‌

P1

P0

=‌

nmgx

mgx

‌

P1

P0

=‌

n

1

⇒P1:P0=n:1