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Question : 154 of 160
Marks:
+1,
-0
Solution:
Let
‌I=∫(‌| 2−sin‌2x |
| 1−cos‌2‌x |
)ex‌dx‌=∫(‌| 2−2sin‌x‌cos‌x |
| 2sin‌2x |
)ex‌dx‌=∫cosec2xex‌dx−∫cot‌x‌ex‌dx‌=−cot‌x‌ex−∫(−cot‌x)ex‌dx‌−∫cot‌x‌ex‌dx+c‌=−cot‌x‌ex+c‌
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