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Question : 147 of 160
Marks:
+1,
-0
Solution:
Given,
‌[atan−1x+b‌log(‌)]=‌ On integrating both sides, we get
‌atan−1x+b‌log(‌)‌=‌‌∫[‌−‌]‌dx‌⇒‌‌atan−1x+b‌log(‌)‌=‌‌log(‌)−‌tan−1x‌⇒‌‌a=−‌,‌‌b=‌‌∴‌‌a−2b=−‌−2(‌)=−1‌
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