EAMCET Engineering 2009 Solved Paper

Section: Mathematics

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Question : 124 of 160

Marks: +1, -0

The point on the line 3x+4y=5 which is equidistant from (1,2) and (3,4) is

(7,−4)
(15,−10)
(1∕7,8∕7)
(0,5∕4)

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