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Question : 114 of 160
Marks:
+1,
-0
Solution:
‌‌ Given, ‌m1=|1|=√22+(−1)2+(1)2=√6‌m2=|2|=√32+(−4)2+(−4)2=√41‌m3=|3|=√12+12+(−1)2=√3‌‌ and ‌m4=|4|=√(−1)2+(3)2+(1)2=√11‌∴‌‌m3<m1<m4<m2‌
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