If f:[-6,6] \to R is defined by f(x)=x^2-3 for x \in R, then (f \circ f \circ f)(-1)+(f \circ f \circ f)(0)+(f \circ f \circ f)(1) is equal to

EAMCET Engineering 2008 Solved Paper

Section: Mathematics

Question : 83 of 160

Marks: +1, -0

If f:[−6,6]→R is defined by f(x)=x2−3 for x∈R, then
(f∘f∘f)(−1)+(f∘f∘f)(0)+(f∘f∘f)(1) is equal to

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