When 25 {\g} of a non-volatile solute is dissolved in 100 {\g} of water, the vapour pressure is lowered by 2.25 \times 10^{-1} {\mm}. If the vapour pressure of water at 20^{\circ} {\C} is 17.5 {\mm}, what is the molecular weight of the solute ?

EAMCET Engineering 2008 Solved Paper

Section: Chemistry

Question : 49 of 160

Marks: +1, -0

When 25g of a non-volatile solute is dissolved in 100g of water, the vapour pressure is lowered by 2.25×10−1‌mm. If the vapour pressure of water at 20∘C is 17.5‌mm, what is the molecular weight of the solute ?

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