EAMCET Engineering 2008 Solved Paper

Section: Mathematics

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Question : 160 of 160

Marks: +1, -0

The solution of the differential equation xy2dy−(x3+y3)‌dx=0 is

y3=3x3+c
y3=3x3‌log(cx)
y3=3x3+log(cx)
y3+3x3=log(cx)

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