© examsiri.com
Question : 119 of 160
Marks:
+1,
-0
Solution:
Given that,
=2+−‌ and ‌=+3Now,
×=||‌=(3−0)−(6+1)+(0−1)‌=3−7−‌ Now, ‌[]‌=⋅(×)‌=|||×|cos‌θ‌=1(√32+72+12)‌cos‌θ‌=√59‌cos‌θ⇒[]max‌=√59⋅1(
∵ maximum value of
cos‌θ is 1 )
© examsiri.com
Go to Question: