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Question : 116 of 160
Marks:
+1,
-0
Solution:
Since, the position vectors
60+3,40−8, and
a−52 are collinear.
∴‌‌||=0 ‌⇒60(−8+52)−3(40−a)‌+1(−2080+8a)=0‌⇒2640−120+3a−2080+8a=0‌⇒‌‌440+11a=0⇒a=−40‌
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