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Question : 104 of 160
Marks:
+1,
-0
Solution:
‌√3‌cosec‌20∘− sec20∘‌‌=‌−‌‌‌=‌| sin‌60∘‌cos‌20∘−sin‌20∘‌cos‌60∘ |
| cos‌60∘‌s‌i‌n‌20∘‌cos‌20∘ |
‌‌=‌| sin‌40∘ |
| cos‌60∘‌s‌i‌n‌20∘‌cos‌20∘ |
‌‌=‌| 2sin‌20∘‌cos‌20∘ |
| (sin‌20∘‌cos‌20∘) |
=4
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