EAMCET Engineering 2007 Solved Paper

Horizontal range of the object fired,
R=‌

u2sin‌2θ

g

At the highest point, when object is exploded into two equal masses, then
or
2mu‌cos‌θ‌=m(0)+mv
v‌=2u‌cos‌θ
It means, the horizontal velocity becomes double at the highest point, hence it will cover double the distance during the remaining flight.
∴ Total horizontal range of the other part
‌=‌

R

2

+R=‌

3R

2

‌=‌

3

2

‌

u2sin‌2θ

g

=‌

3

2

×‌

(100)2×2sin‌θ‌cos‌θ

g

‌=‌

3

2

×‌

(100)2×2× 3 5 × 4 5

10

=1440m