\int \frac{ \sin x+8 \cos x}{4 \sin x+6 \cos x} \dx is equal to

Correct Answer is : x+12log(4sinx+6cosx)+c

x+\frac{1}{2} \log (4 \sin x+6 \cos x)+c

\frac{1}{2} \log (4 \sin x+6 \cos x)+c

EAMCET Engineering 2007 Solved Paper

Section: Mathematics

Question : 153 of 160

Marks: +1, -0

∫‌

sin‌x+8‌cos‌x

4sin‌x+6‌cos‌x

‌dx is equal to

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