© examsiri.com
Question : 119 of 160
Marks:
+1,
-0
Solution:
Given,
=a1+a2+a3‌ Now, ‌|×|2‌=(×)⋅(×)‌=(a3−a2)⋅(a3−a2)‌=a32+a22 |×|2‌=(a1−a3)⋅(a1−a3)‌=a12+a32|×|2‌=(a1+a1)⋅(a2−a1)‌=a22+a12Now,
|×|2‌+|×|2+|×|2‌=2(a12+a22+a32)‌=2||2 Hence, both A and
R are true and
R is correct reason for A.
© examsiri.com
Go to Question: