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Question : 115 of 160
Marks:
+1,
-0
Solution:
Given vectors
=2++,=6−+2 and
=14−5+p are collinear, therefore
‌[]=0‌⇒‌‌||=0‌⇒2[−p+10]−1[6p−28]+1[−30+14]=0‌⇒‌‌−2p+20−6p+28−16=0‌⇒‌‌−8p+32=0‌⇒‌‌p=4‌
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