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Question : 99 of 160
Marks:
+1,
-0
Solution:
‌|| log‌e | log‌e2 | log‌e3 |
| log‌e2 | log‌e3 | log‌e4 |
| log‌e3 | log‌e4 | log‌e5 |
| =|| log‌e | 2‌log‌e | 3‌log‌e |
| 2‌log‌e | 3‌log‌e | 4‌log‌e |
| 3‌log‌e | 4‌log‌e | 5‌log‌e |
|‌‌‌=||‌=||C2→C2−C1‌=0 (
∵ Two columns are identical)
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