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Question : 97 of 160
Marks:
+1,
-0
Solution:
‌∵‌‌A=[]‌∴‌‌A2=[][]‌=[]‌A3=A2⋅A=[][]‌=[]‌∴A3−4A2−6A‌=[]−4[]−6[]‌=[| 41−36−6 | 42−32−12 | 42−32−12 |
| 42−32−12 | 41−36−6 | 42−32−12 |
| 42−32−12 | 42−32−12 | 41−36−6 |
]‌=[| −1 | −2 | −2 |
| −2 | −1 | −2 |
| −2 | −2 | −1 |
]‌=−[]=−A‌
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