If |x| < 1 and y=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+. . ., then x is equal to :

Correct Answer is : y+y22!+y33!+...

y+\frac{y^2}{2}+\frac{y^3}{3}+. . .

y-\frac{y^2}{2}+\frac{y^3}{3}-\frac{y^4}{4}+. . .

y+\frac{y^2}{2 !}+\frac{y^3}{3 !}+. . .

y-\frac{y^2}{2 !}+\frac{y^3}{3 !}-\frac{y^4}{4 !}+. . .

EAMCET Engineering 2006 Solved Paper

Section: Mathematics

Question : 93 of 160

Marks: +1, -0

If |x|<1 and y=x−‌

+‌

−‌

+..., then x is equal to :

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