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Question : 141 of 160
Marks:
+1,
-0
Solution:
‌f(x)=exsin‌x
∴‌f′(x)=ex‌cos‌x+sin‌xex
⇒f′′(x)=ex‌cos‌x−exsin‌x+exsin‌x
‌‌‌+ex‌cos‌x
‌‌‌=2ex‌cos‌x
‌‌ Now, ‌f′′′(x)‌=−2exsin‌x+2ex‌cos‌x
‌ and ‌fiv(x)‌=−2exsin‌x−2ex‌cos‌x
‌+2ex‌cos‌x−2exsin‌x
‌=−4exsin‌x
fv(x)‌=−4ex‌cos‌x−4exsin‌x
fvi(x)‌=−4ex‌cos‌x+4exsin‌x+4exsin‌x
‌−4ex‌cos‌x
=‌−8ex‌cos‌x
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