EAMCET Engineering 2006 Solved Paper

The separate equation of pair of straight lines of 12x2−20xy+7y2=0 are (6x−7y)=0 and (2x−y)=0
These the equation of sides are
6x−7y=0 . . . (i)
2x−y=0 . . . (ii)
and 2x−3y+4=0 . . . (iii)
On solving these equations, taking two at a time we get the vertices of a triangle which are A(0,0);B(1,2) and (7,6).
∴ Centroid of a triangle is (‌

0+1+7

3

,‌

0+2+6

3

)
i.e., ‌‌(‌

8

3

,‌

8

3

)