{\bo {a}}^{\to} \cdot \stackrel{\^}{\bo {i}}={\bo {a}}^{\to} \cdot(2 \stackrel{\^}{\bo {i}}+\stackrel{\^}{\bo {j}})={\bo {a}}^{\to}(\stackrel{\^}{\bo {i}}+\stackrel{\^}{\bo {j}}+3 \stackrel{\^}{\bo {k}})=1, then {\bo {a}}^{\to} is equal to :

Correct Answer is : 1∕3(3^i−3^j+^k)

\stackrel{\^}{{i}}-\stackrel{\^}{ {k}}

1 \/ 3(3 \stackrel{\^}{{i}}+3 \stackrel{\^}{\bo {j}}+\stackrel{\^}{ {k}})

1 \/ 3(\stackrel{\^}{ {i}}+\stackrel{\^}{\bo {j}}+\stackrel{\^}{ {k}})

1 \/ 3(3 \stackrel{\^}{ {i}}-3 \stackrel{\^}{\bo {j}}+\stackrel{\^}{ {k}})

EAMCET Engineering 2006 Solved Paper

Section: Mathematics

Question : 118 of 160

Marks: +1, -0

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⋅(2

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)=1, then

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is equal to :

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