EAMCET Engineering 2005 Solved Paper

For, At1∕2=1‌min
∴ part of A remained after 4 minutes
‌ (i.e., ‌4‌ half- life) will be ‌=‌

1

16

∴ part of A disintegrated in the same period =‌

15

16

For B,t1∕2=2‌min
∴ Part of B remained after 4 minutes (i.e., 2 half life) =‌

1

4

∴ part of B disintegrated in the same time =‌

3

4

Hence, ratio of disintegrated weights of A and
B=‌

15

16

:‌

3

4

=15:12=5:4